If it's not what You are looking for type in the equation solver your own equation and let us solve it.
r in (-oo:+oo)
12 = ((3^(1/2))/4)*r^2 // - ((3^(1/2))/4)*r^2
12-(((3^(1/2))/4)*r^2) = 0
((3^(1/2))/4)*r^2 = -12 // : (3^(1/2))/4
r^2 = -48*3^(-1/2)
r belongs to the empty set
| 0=4hw+2w^2-54 | | -6x+16=-8x | | 7x+12=7x+16 | | 25x+12y=53 | | -6(p-11)=-43-6p | | (5v+2)(3-v)=0 | | 1/5x^3=4 | | n-11=-5(5+10n)-5(1-5n) | | (x-12)(x-4)=9 | | 20x=6.99 | | 0=4x(x+2) | | 92+y=-20 | | 40x+14(1.5x)=1250 | | 20o=6.99 | | 12w=168 | | 40x*14(1.5x)=1250 | | 11(-5-7b)=-11(6b+7) | | 10592*0.015=x | | =t^2-2 | | 3d+3d=3d+5 | | 18u=2(8u-6)-14 | | -2x+6+3x=4 | | 18+3(-6v+6)=18-18v+18 | | 3(-4j+4)=12-12j | | =u^2-4u+3v^2-7u-21v | | 4+4h-14=4(h+3) | | x/23=276 | | 2(20y+20)=-5(-8y-8) | | 6-2d=12 | | 5c-4c+7=6 | | -13m=-10+2(-7m-5) | | -9-2(12r+2)=-15r-13-9r |